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What Is The Mass Percent?

The metal content of iron in ores can be determined by a redox procedure in which the sample is first oxidized with Br2 to convert all the iron to Fe^3+ and then titrated with Sn^2+ to reduce the Fe^3+ to Fe^2+.  The balanced equation is:

2Fe^3+(aq)+Sn^2+(aq)—->2Fe^2+(aq)+Sn^4+(aq)

What is the mass percent of Fe in a .1875g sample of ore if 13.28mL of a .1015M Sn^2+ solution is needed to titrate the Fe^3+?

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Posted on September 30, 2013, in #question and tagged , , , , , , . Bookmark the permalink. 1 Comment.

  1. .01328(.1015M)(2molFe/1mol)(55.85gFe/1mol) = .1505
    .1505/.1875 (100) = 80.3%

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