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Calculating Mass Percent

The metal content of iron in ores can be determined by a redox procedure in which the sample is first oxidized with Br2 to convert all the iron to Fe3+ and then titrated with Sn2+ to reduce the Fe3+ to Fe2+. The balanced equation is
2Fe3+(aq)+Sn2+(aq)→2Fe2+(aq)+Sn4+(aq)

What is the mass percent Fe in a 0.1900g sample if 12.50mL of a 0.1015 M Sn2+ solution is needed to titrate the Fe3+?

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Posted on September 30, 2013, in #question and tagged , , , , . Bookmark the permalink. 1 Comment.

  1. .0125L(.1015MSn/1L)(2MolFe/1MolSn)(55.845gFe/1MolFe)=.1417
    .1417/.1900(100)=74.5%

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