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Blood Alcohol Levels

Blood alcohol levels can be determined from a redox reaction with potassium dichromate according to the balanced equation…

C2H5OH(aq)+2Cr2O7^2-(aq)+16H^+(aq)—->2CO2(g)+4Cr^3+(aq)+11H2O(l)

What is the blood alcohol level in mass percent if 8.76mL of .04988M K2Cr2O7 is required for complete reaction with a 10.002g sample of blood?

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Posted on September 30, 2013, in #question and tagged , , , , , , , , , . Bookmark the permalink. 1 Comment.

  1. .00876mL(.04988M)(1mol/2mol)(46.07g/1mol) = .01007
    .01007/10.002 (100) = .101%

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